Josspixjn72

Multiply 4 4 by 1 1 Subtract 9 4 9 4 from 0 0 Substitute the values of a a, d d, and e e into the vertex form a ( x d) 2 e a ( x d) 2 e Set y y equal to the new right side Use the vertex form, y = a ( x h) 2 k y = a ( x − h) 2 k, to determine the values of a a, h h, and k kSince this tells us that the yintercept is Remember the yintercept is the point where the graph intersects with the yaxis So we have one point Now since the slope is comprised of the "rise" over the "run" this means Also, because the slope is , this means which shows us that the rise is 2 and the run is 317/3/18 See a solution process below First, solve for two points which solve the equation and plot these points First Point For x = 0 y = 2/3 xx 0 y = 0 or (0, 0) Second Point For x = 3 y = 2/3 xx 3 y = 6/3 y = 2 or (3, 2) We can next plot the two points on the coordinate plane graph{(x^2y^035)((x3)^2(y2)^035)=0 10, 10, 5, 5} Now, we can draw a 1 Y = 3x^2 - x^3 graph

Quadratic Function  I'm trying to solve this problem Find the equation of the tangent to the parabola y = x 2 If the xintercept of the tangent is 2 All what I can think of is finding the slope which is d y / dFor a parabola y 2 = 4ax, the equation of the normal passing through the point (x1,y1) ( x 1, y 1) and having a slope of m = y1/2a, the equation of the normal is (y−y1) = −y1 2a (x− x1) ( y − y 1) = − y Parabola y=x^2-2 direfleksikan